{
"cells": [
{
"cell_type": "markdown",
"metadata": {},
"source": [
"### Introducción al Cálculo de Probabilidades para Estudiantes de Ingeniería\n",
"#### Código Capítulo 1.\n",
"#### `Julia`"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"### Bloque de código 1.1"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"ω = [3.4, 4.5, 1.6, 3.1, 2.2, 1.9, 4.5, 2.1, 0.9]\n",
"sum(ω)\n",
"prod(ω)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"### Operador de rango"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"sum(ω[3,4,5,6,7])\n",
"sum(ω[3:7])"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"### Símbolos en `Julia`"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"∑ = sum\n",
"∑(ω)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"### Bloque de código 1.2"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"sum(sqrt.(1:100))\n",
"prod(sqrt.(1:100))"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"### Despacho múltiple"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"sum(sqrt, 1:100)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"### Cálculos Ejemplo 1.2"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"sum((0:6) .+ 3)/3\n",
"sum(0:6)/3 + 6"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"### Bloque de código 1.3"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"lluvia = [ 1.9, 2.0, 2.9, 3.5, 6.7, 7.1, 7.6, 10.0,\n",
" 10.4, 13.9, 14.6, 18.4, 21.9, 27.1, 27.5]\n",
"mean(lluvia)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"### Bloque de código 1.4"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"x₁ = 0.01\n",
"Δx = 0.01\n",
"x₉₉ = 1 - Δx\n",
"P = x₁:Δx:x₉₉\n",
"Δx*sum(P.*(1.0 .- P))\n",
"Δx*sum( x -> x*(1.0 - x), P)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"### Definición anónima de una función"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"map( x -> x^2+1, ω)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"### Definición de una función"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"f(x) = x*(1-x)"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"Δx*sum(f, P)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"### Suma acumulada"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"cumsum(ω)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"### Definición general de una función"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"function s(x)\n",
" k = 0:floor(x)\n",
" o = k .* (10 .- k)\n",
" oc = cumsum(o)\n",
" return oc ./165\n",
"end"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"### Factorial"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"n = 3\n",
"factorial(n)"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"factorial(0)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"### Coeficiente binomial"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"binomial(10,6)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"### Conjuntos"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"A = Set([♠,♡,♣,♢])\n",
"B = Set([π, γ, ϕ])"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"### Bloque de código 1.5"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"A = Set([0,2,4,6,8,10]) \n",
"0 in A ? 1 : 0 \n",
"1 in A ? 1 : 0 "
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"### Bloque de código 1.6"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"lluvia20 = lluvia .> 20\n",
"prop20 = sum(lluvia20)/15"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"mean(lluvia .> 20)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"### Bloque de código 1.7"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"function Ia(x)\n",
" A = Set([0,2,4,6,8,10])\n",
" res = x in A ? 1 : 0 \n",
" return res\n",
"end"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"Ia(0)"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"Ia(4.5)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"### Bloque de código 1.8"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"function Ib(x)\n",
" res = (x>0)&(x<1) ? 1 : 0 \n",
" return res\n",
"end"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"Ib(0)"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"Ib(0.25)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"### Bloque de código 1.9"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"function t(x)\n",
" if (x<0)|(x>2)\n",
" res = 0\n",
" elseif x<1\n",
" res = x^2\n",
" else\n",
" res = (x-2)^2\n",
" return res\n",
" end\n",
"end"
]
}
],
"metadata": {
"kernelspec": {
"display_name": "Julia 1.10.4",
"language": "julia",
"name": "julia-1.10"
},
"language_info": {
"file_extension": ".jl",
"mimetype": "application/julia",
"name": "julia",
"version": "1.10.4"
},
"orig_nbformat": 4
},
"nbformat": 4,
"nbformat_minor": 2
}